I've measured feeding SOAPMessage with SAXSource to be about 50% faster than internal SAAJ parsing implementation used in the accepted answer: SOAPMessage message = messageFactory.createMessage()
This works for me: SOAPMessage sm = MessageFactory.newInstance(SOAPConstants.SOAP_1_2_PROTOCOL).createMessage(new MimeHeaders(), is) SOAPMessage request = MessageFactory.newInstance().createMessage(null, is) InputStream is = new ByteArrayInputStream(send.getBytes()) Here is a C++ program is given to encode a message using Playfair Cipher.Convert the String into an input stream, then read it into the SOAP message factory.
Receiver has the same key and can create the same key table, and then decrypt any messages made using that key. Using these rules, the result of the encryption of ‘hide money’ with the key of ‘tutorials’ would be − QC EF NU MF ZVĭecrypting the Playfair cipher is as simple as doing the same process in reverse. If neither of the preceding two rules are true, form a rectangle with the two letters and take the letters on the horizontal opposite corner of the rectangle. If both letters are in the same row, take the letter to the right of each one (going back to the left if at the farthest right)‘D’ and ‘E’ are in same row, hence take letter to the right of them to replace. If both the letters are in the same column, take the letter below each one (going back to the top if at the bottom)‘H’ and ‘I’ are in same column, hence take letter below them to replace. Let us consider that, we want to encrypt the message “hide money”. If there is an odd number of letters, a Z is added to the last letter. The key table works out to be −įirst, a plaintext message is split into pairs of two letters (digraphs). The rest of the table will be filled with the remaining letters of the alphabet, in natural order. In a key table, the first characters (going left to right) in the table is the phrase, excluding the duplicate letters. The sender and the receiver deicide on a particular key, say ‘tutorials’. If the plaintext contains J, then it is replaced by I. Each of the 25 alphabets must be unique and one letter of the alphabet (usually J) is omitted from the table as we need only 25 alphabets instead of 26. The key table is a 5×5 grid of alphabets that acts as the key for encrypting the plaintext. In playfair cipher, initially a key table is created. In this scheme, pairs of letters are encrypted, instead of single letters as in the case of simple substitution cipher.
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